题解 | #扑克牌顺子#

import java.util.*;

public class Solution {
    public boolean IsContinuous(int [] numbers) {
        Arrays.sort(numbers);
        int j = 0;
        int m = 0;
        for (int i = 0; i < numbers.length; i++) {
            if (numbers[i] == 0) {
                j++;
            } else {
                if (i + 1 < numbers.length && numbers[i] + 1 != numbers[i + 1]) {
                    m += (numbers[i + 1] - numbers[i] - 1);
                }
                if (i + 1 < numbers.length && numbers[i] == numbers[i + 1]){
                    return false;
                }
            }
        }
        if (m > j) { // 统计0的个数和不连续的个数。大于则不连续。
            return false;
        }
        return true;
    }
}