- 只要找到重复数字的左边界。之后迭代判断即可。
class Solution { public: int GetNumberOfK(vector<int> data ,int k) { if(!data.size()) return 0; int res = 0; int left = 0; int right = data.size()-1; while(left<right){ int mid = (left+right)/2; if(data[mid]==k){ right = mid; }else if(data[mid]<k){ left = mid + 1; }else{ right = mid; } } for(;left< data.size();left++){ if(data[left]==k) res++; } return res; } };