题解 | #求最大连续bit数#

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextInt()) { // 注意 while 处理多个 case
            int i = in.nextInt();
            String binaryString = Integer.toBinaryString(i);
            char[] chars = binaryString.toCharArray();
            int max = 0;
            int count = 0;
            for (int j = 0; j < chars.length; j++) {
                if (chars[j] == '1') {
                    count++;
                    if (j == chars.length - 1)
                        max = Math.max(max, count);
                    continue;
                }
                max = Math.max(max, count);
                count = 0;
            }

            System.out.println(max);
        }
    }
}