特判1 2 3这些数据就行,因为后面的数据不需要改变,第i个就是i,i+i=2i,肯定不是质数。

#include <iostream>
#include <queue>
#include <map>
#include <set>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <iomanip>
#include <stack>
#include <numeric>
#include <ctime>
#include <string>
#include <bitset>
#include <unordered_map>
#include <unordered_set>

using namespace std;
using ll = long long;
const ll N = 1e6 + 5, mod = 1e9 + 7, inf = 0x3f3f3f3f;

int n;

void solve() {
    cin >> n;
    if (n <= 2) {
        cout << -1 << '\n';
        return ;
    }

    cout << 3 << " " << 2 << " " << 1 << " ";

    for (int i = 4; i <= n; i++) {
        cout << i << " ";
    }
}

int main() {
    ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);

    int t = 1;
    //cin>>t;

    while (t--) {

        solve();

    }

    return 0;
}