特判1 2 3这些数据就行,因为后面的数据不需要改变,第i个就是i,i+i=2i,肯定不是质数。
#include <iostream>
#include <queue>
#include <map>
#include <set>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <iomanip>
#include <stack>
#include <numeric>
#include <ctime>
#include <string>
#include <bitset>
#include <unordered_map>
#include <unordered_set>
using namespace std;
using ll = long long;
const ll N = 1e6 + 5, mod = 1e9 + 7, inf = 0x3f3f3f3f;
int n;
void solve() {
cin >> n;
if (n <= 2) {
cout << -1 << '\n';
return ;
}
cout << 3 << " " << 2 << " " << 1 << " ";
for (int i = 4; i <= n; i++) {
cout << i << " ";
}
}
int main() {
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int t = 1;
//cin>>t;
while (t--) {
solve();
}
return 0;
}

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