题解 | 提取不重复的整数

#include <iostream>
#include<vector>
using namespace std;

int result[10] = {0};
int main() {
    int data;
    cin>>data;
    vector<int>shu;
    vector<int> test;
    while(data!=0){
        shu.push_back(data%10);
        data/=10;
    }
    for (int k = 0; k<shu.size(); k++) {
        if(result[shu[k]] == 0){
            cout<<shu[k];
            result[shu[k]] = 1;
        }
        else{
            continue;
        }
    }
    cout<<endl;
}
// 64 位输出请用 printf("%lld")