select gender,university,count(id) as user_num,AVG(active_days_within_30) as avg_active_day,AVG(question_cnt) as avg_question_cnt from user_profile group by gender, university order by gender,university;

select gender,university,count(id) as user_num,AVG(active_days_within_30) as avg_active_day,AVG(question_cnt) as avg_question_cnt from user_profile group by gender, university order by gender,university;