题解 | #日期累加#

/*这题果然跨年，烦*/

#include <iostream>
#include <cstdio>

using namespace std;

int m1[12]= {31,29,31,30,31,30,31,31,30,31,30,31};
int m2[12]= {31,28,31,30,31,30,31,31,30,31,30,31};

int main()
{
    int n;
    scanf("%d",&n);
    int year,month,day,add;
    while(scanf("%d%d%d%d",&year,&month,&day,&add)!=EOF){
        int month2;
        int day2=day+add;
        for(int i=month-1;;++i){
            if(i>11)
            {
                year++;
                i=(i+1)%12-1;
            }
            if((year%4==0&&year%100!=0)||year%400==0){
                month2=i+1;
                if(day2<=m1[i]){
                    break;
                }
                day2=day2-m1[i];
            }
            else{

                month2=i+1;
                if(day2<=m2[i]){
                    break;
                }
                day2=day2-m2[i];
            }
        }
        printf("%d-%02d-%02d\n",year,month2,day2);
    }
}