#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 2e5+10;
ll b[N];
ll pres[N];
void solve(){
int n,q;
cin>>n>>q;
for(int i=1;i<=n;i++)
{
cin>>b[i];
pres[i] = pres[i-1]+b[i];
}
while(q--)
{
ll t;
cin>>t;
int ans = upper_bound(pres+1,pres+1+n,t)-pres;
cout<<ans<<'\n';
}
}
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t=1;
// cin>>t;
while(t--)
{
solve();
}
return 0;
}
二分模板题

京公网安备 11010502036488号