题解 | #高精度整数加法#

a = input()
b = input()
if len(b) <= len(a):
	b = b.rjust(len(a),"0")
else:
	a = a.rjust(len(b),"0")
#先对齐补位

c = list(map(int,a[::-1]))
d = list(map(int,b[::-1]))
逆序按位相加

e = []
tag = 0 # 进位标志
for i in range(len(c)):
	if c[i] + d[i] + tag > 9:
		e.append(c[i] + d[i]  + tag - 10)
		tag = 1
	else:
		e.append(c[i] + d[i]  + tag)
		tag = 0
if tag: #溢出判断，最后溢出了则补1
	e.append(1)
print("".join([str(x) for x in e[::-1]]))