题解 | #合并两个排序的链表#

/*
struct ListNode {
    int val;
    struct ListNode *next;
    ListNode(int x) :
            val(x), next(NULL) {
    }
};*/
class Solution {
public:
    ListNode* Merge(ListNode* pHead1, ListNode* pHead2) {
        //如果链表1或2为空
        if(!pHead1) return pHead2;
        if(!pHead2) return pHead1;
        //递归
        if(pHead1->val < pHead2->val)
        {
            pHead1->next = Merge(pHead1->next, pHead2);
            return pHead1;
        }
        else
        {
            pHead2->next = Merge(pHead2->next, pHead1);
            return pHead2;
        }
    }
};