题解 | 奇偶统计

#include <bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cin >>n;
    if(n %2 == 0)
    {
        cout << n /2<<" "<<n/2;
        return 0;
    }
    else
    {
        cout << (n + 1)/2<<" "<<((n+1)/2)-1;
        return 0;
    }  
}