题解 | 字母异位词的长度

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param s string字符串 
# @param c string字符串 
# @return int整型
#
class Solution:
    def isCongruent(self , s: str, c: str) -> int:
        # write code here
        dic={}
        for char in s:
            if char not in dic:
                dic[char]=1
            else:
                dic[char]+=1
        for char in c:
            if char not in dic:
                return -1
            else:
                dic[char]-=1
                if dic[char]==0:
                    del dic[char]
        if len(dic)==0:
            return len(s)
        else:
            return -1