题解 | #合并k个已排序的链表#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param lists ListNode类一维数组 
# @return ListNode类
#
class Solution:
    def mergeKLists(self , lists: List[ListNode]) -> ListNode:
        # write code here
        if lists is None: return None
        result = []
        for pHead in lists:
            while pHead:
                result.append(pHead.val)
                pHead = pHead.next
        if len(result) == 0: return None
        result.sort()
        head1 = NewHead = ListNode(0)
        for data in result:
            NewHead.next = ListNode(0)
            NewHead = NewHead.next
            NewHead.val = data
            
        return head1.next