题解 | 牛牛的替换

#include <stdio.h>

int main() {
    int num;
    char m,n,x,y;
    scanf("%d %c %c %c %c",&num,&m,&n,&x,&y);
    char sen[100];
    scanf("%s",sen);
    char *p=sen;
    while(*p!='\0')
    {
        if(*p==m)
        *p=n;
        p++;
    }
    p=sen;
    while(*p!='\0')
    {
        if(*p==x)
        *p=y;
        p++;
    }
    puts(sen);
    return 0;
}