题解 | #统计数据正负个数#

#include<stdio.h>
int main()
{
	int n1[10] = { 0 }; 
	for (int i = 0; i < 10; i++)
	{
		scanf("%d", &n1[i]);  
	}
	int count1 = 0; 
	int count2 = 0;  
	for (int i = 0; i < 10; i++)
	{
		if (n1[i]>=0)
			 count1++;
		else 
			 count2++;  
	}
	printf("positive:%d\nnegative:%d", count1, count2);  
	return 0; 
}