题解 | #字符框#

水题

直接暴力模拟

#include <iostream>
#include <cstring>
#include <algorithm>
#include <string> 
using namespace std; 
int n, m; 
string a[55]; 
int main()
{
  cin >> n >> m;
  for (int i = 1; i <= n; i ++ )
      cin >> a[i];

  int res = 0;
  int i = 1, j = 0;
  while(1)
  {
      string ch;
      ch = a[i].substr(j,2) + a[i+1].substr(j,2);  //每次截取的四个字母组成的字符串
      if(ch.find('f') != -1)
          if(ch.find('a') != -1)
              if(ch.find('c') != -1)
                  if(ch.find('e') != -1)
                      res ++;                      //字符串同时存在face四个字母时 答案++

      //cout << ch << endl;

      j ++;                                        //每次4格截取右移一位
      if (j == m-1)                                
      {
          j = 0;
          i ++;
      }

      if (ch.size() != 4)                         //截取不足4字母时退出循环
          break;
  }
  cout << res << endl;
}