# 获取8月份用户 select a.device_id, a.university, count( question_id) as question_cnt, sum(case when result = 'right' then 1 else 0 end ) as right_question_cnt from user_profile a left join( select * from question_practice_detail where month(date) = '08') b on a.device_id = b.device_id where a.university = '复旦大学' GROUP BY a.device_id, a.university

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