with d as ( select id,job,score, dense_rank () over(partition by job order by score) rk, count(*) over(partition by job) total from grade ) select d.job, round(d.total/2,0) as start, (case when d.total%2 !=0 then round(d.total/2,0) else round(d.total/2+1,0) end)as end from d group by d.job order by d.job