1.动态规划递归版g(M)表示从矩阵M[:n][:m]右下角走到左上角的最小路径长度递归式为:g(A) = min(g(M[:n][:m-1]), g(M[:n-1][:m])) + M[n-1][m-1]递归基:当矩阵为一行或者一列时,即当n==1或者m=1时,g(M)=sum(M) # 动态规划-递归 def minPathSum(self , matrix ): n = len(matrix) m = len(matrix[0]) if n==1: sum_ = 0 for i...