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题解 | #合法IP#

def f(ip): if len(ip) != 4: return False else: for i in ip: if not i.isdigit(): return False ...

2024-03-22

0 160

题解 | #找出字符串中第一个只出现一次的字符#

s = input() dic = {} for i in s: if i not in dic: dic[i] = dic.get(i,0) + s.count(i) if dic[i] == 1: print(i) break ...

2024-03-20

0 179

题解 | #找出字符串中第一个只出现一次的字符#

s = input() dic = {} for i in s: if i not in dic: dic[i] = dic.get(i,0) + s.count(i) if dic[i] == 1: print(i) break ...

2024-03-20

0 183

题解 | #字符串加密#

A = 'abcdefghijklmnopqrstuvwxyz' # 字母表A # trailbzescdfghjkmnopquvwxy keyy = input() # 初始密钥 s = input() # 要加密的字符串，即明文 ke = '' res = '' # 去重 for ...

2024-03-19

0 182

题解 | #整数与IP地址间的转换#

ip = list(map(int,input().split('.'))) # 10.0.3.193 n = int(input()) # 167969729 ans = '' # ip -> int for i in ip: ans += (bin(i)[2...

2024-03-19

0 212

题解 | #密码截取#

s = input() p = 0 for i in range(len(s)): for j in range(len(s)-1,i-1,-1): if s[i] == s[j] and s[i+1:j] == s[j-1:i:-1] and j-i+1 > p: ...

2024-03-19

0 158

题解 | #密码截取#

s = input() p = 0 for i in range(len(s)): for j in range(len(s)-1,i+1,-1): if s[i] == s[j] and s[i+1:j] == s[j-1:i:-1] and j-i+1 > p: ...

2024-03-19

0 164

题解 | #密码截取#

s = input() p = 0 for i in range(len(s)-1): for j in range(len(s)-1,i+1,-1): if s[i] == s[j] and s[i+1:j] == s[j-1:i:-1] and j-i+1 > p:...

2024-03-19

0 167

题解 | #字符串加解密#

A = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz' B = '1234567890bcdefghijklmnopqrstuvwxyzaBCDEFGHIJKLMNOPQRSTUVWXYZA' s1 = input(...

2024-03-19

0 179

题解 | #查找兄弟单词#

while True: try: s = input().split() n = int(s[0]) x = s[-2] k = int(s[-1]) xx = s[1:-2] # 兄弟单词 ...

2024-03-18

0 236