柚茶_Rola
柚茶_Rola
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题解 | #公共子串计算#
s1 = input().lower() s2 = input().lower() if len(s1) > len(s2): s1,s2 = s2,s1 p = 0 for i in range(0,len(s1)): for j in range(i,len(s1)): ...
2024-10-26
0
32
题解 | #参数解析#
s = input() #1 如果s中不存在引号,则直接用空格分 ls = [] if '"' not in s: ss = s.split() for i in ss: ls.append(i) #2 如果s中有引号,则先用引号分再用空格分 else: ...
2024-10-26
0
42
题解 | #字符串通配符#
while True: try: s1 = input() s2 = input() # 初始化dp数组 dp = [[False for j in range(len(s2) + 1)] for i in range(len(...
2024-10-25
0
34
题解 | #字符串通配符#
while True: try: s1 = input() s2 = input() m = len(s1) n = len(s2) dp = [[False for j in range(n+1)] for i...
2024-10-25
0
28
题解 | #矩阵乘法计算量估算#
n = int(input()) ls = [] for i in range(n): ls.append(list(map(int,input().split()))) s = input() # (A(BC)) stack = [] cc = 0 for i in s: if i...
2024-10-25
0
37
题解 | #矩阵乘法#
x = int(input()) y = int(input()) z = int(input()) A = [] B = [] C = [[0 for j in range(z)] for i in range(x)] for i in range(x): A.append(list(m...
2024-10-25
0
55
题解 | #矩阵乘法#
from pickle import LIST x = int(input()) y = int(input()) z = int(input()) A = [] B = [] C = [[0 for j in range(z)] for i in range(x)] for i in range...
2024-10-25
0
40
题解 | #24点游戏算法#
def f(ls,tar): if len(ls) == 1: return ls[0] == tar else: for i in range(len(ls)): t = ls[i] m = ls[:i...
2024-10-25
0
69
题解 | #配置文件恢复#
while True: try: ke = ['reset','reset board','board add','board delete','reboot backplane','backplane abort'] val = ['res...
2024-10-25
0
37
题解 | #MP3光标位置#
n = int(input()) s = input() # UUUU song = [] for i in range(1,n+1): song.append(i) f = 1 # f表示当前页第一首歌的位置。代表翻页。 p = 1 # 光标位置 光标初始的位置为第1首歌(p = [1,2...
2024-10-24
0
53
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