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题解 | 牛客的课程订单分析(七)
with t1 as( select oi.id as id, user_id, count(user_id)over(partition by user_id) as course_cnt, product_name, ...
2025-11-07
0
15
题解 | 牛客的课程订单分析(六)
with t1 as( select oi.id as id, user_id, count(user_id)over(partition by user_id) as course_cnt, product_name, ...
2025-11-07
0
16
题解 | 牛客的课程订单分析(五)
with t1 as( select user_id, count(user_id)over(partition by user_id) as course_cnt, date, dense_rank()over(partiti...
2025-11-07
0
18
题解 | 牛客的课程订单分析(四)
with t1 as( select user_id, date, dense_rank()over(partition by user_id order by date) as date_rank, count(user_id...
2025-11-07
0
15
题解 | 牛客的课程订单分析(三)
with t1 as( select user_id, product_name, status, date, count(status)over(partition by user_id) as counts ...
2025-11-07
0
25
题解 | 牛客的课程订单分析(二)
with t1 as( select user_id, product_name, status, date, count(status)over(partition by user_id) as counts ...
2025-11-07
0
19
题解 | 牛客的课程订单分析(一)
# 成功购买 c++或者java或者python id排序 select * from order_info where status='completed' and product_name in('C++','Java','Python') and...
2025-11-07
0
20
题解 | 考试分数(五)
with t1 as( select id, job, score, dense_rank()over(partition by job order by score desc) as t_rank, count...
2025-11-07
0
17
题解 | 考试分数(四)
with t1 as( select job, floor((count(*)+1)/2) as start, ceiling((count(*)+1)/2) as end from grade group by...
2025-11-07
0
18
题解 | 考试分数(三)
# 每个岗位排名前2 with t1 as( select grade.id as id, name, score, dense_rank()over(partition by name order by score desc)...
2025-11-07
0
14
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