跪求要一个offer
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算法和编程题解
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题解 | #二叉搜索树的第k个节点#
* struct TreeNode { * int val; * struct TreeNode *left; * struct TreeNode *right; * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * ...
C++
2022-01-11
0
239
题解 | #删除记录(二)#
delete from exam_record where submit_time is null #sql中使用timestampdiff函数获取时间差 or timestampdiff(minute,start_time,submit_time)<5 order b...
Mysql
2022-01-10
0
153
题解 | #计算用户8月每天的练题数量#
#使用sql中的substring_index字符串截取函数 SELECT SUBSTRING_INDEX(date,"-",-1) as day, count(question_id) as question_cnt from question_practice_detail where ...
Mysql
2022-01-09
0
175
题解 | #记录点赞用户#
public class Main { public static void main(String[] args) { LikeRecorder recorder = new LikeRecorderImpl(); Scanner scanner = n...
Java
2022-01-07
0
217
题解 | #友元全局函数#
using namespace std; class Person { // write your code here...... friend void showAge(Person &); public: Person(int age...
C++
2022-01-06
0
253
题解 | #截取出年龄#
select #sql中subString_index的嵌套使用的用法 SUBSTRING_INDEX(SUBSTRING_INDEX(profile,',',3),',',-1) as age, count(device_id) as NUMBER from user_s...
Mysql
2022-01-06
0
180
题解 | #统计每种性别的人数#
#sql中分割字符串的方法 select SUBSTRING_INDEX(profile,',',-1) as gender, COUNT(device_id) as NUMBER from user_submit group by gender;
Mysql
2022-01-05
0
236
题解 | #计算25岁以上和以下的用户数量#
select ( case when age>=25 then '25岁及以上' else '25岁以下' end) as age_cut, count(device_id) as number...
Mysql
2022-01-05
0
268
题解 | #栈的压入、弹出序列#
public: bool IsPopOrder(vector<int> pushV,vector<int> popV) { bool flag=true; stack<int> test; int i; ...
C++
2022-01-04
0
215
题解 | #去除字符串中重复的字符#
#include<set> // write your code here...... using namespace std; int main() { char str[100] = { 0 }; cin.getline(str, sizeof(str)); ...
C++
2022-01-02
0
219
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