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题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

import java.util.ArrayList; public class Solution { public ArrayList<ArrayList > FindContinuousSequence(int sum) { ArrayList<ArrayList> re...

Java

2022-01-01

0 425

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

import java.util.ArrayList; public class Solution { public ArrayList<ArrayList > FindContinuousSequence(int sum) { ArrayList<ArrayList> re...

Java

2022-01-01

0 351

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

//主要解决指针移动问题就好了 public class Solution{ public int GetUglyNumber_Solution(int index){ if(index <= 6) return index; int p1 = 0; int p2 = 0; int p3 = ...

Java

2022-01-01

0 320

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

public class Solution{ public int GetUglyNumber_Solution(int index){ if(index <= 6) return index; int p1 = 0; int p2 = 0; int p3 = 0; int[] result ...

Java

2022-01-01

0 327

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

public class Solution{ public int NumberOf1Between1AndN_Solution(int n){ int count = 0,bitNum = 1,high = n /10,cur = n % 10,low = 0; while(cur != 0 ||...

Java

2021-12-31

0 255

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

import java.util.*; public class Solution{ public int StrToInt(String s){ s = s.trim(); char[] arr = s.toCharArray(); boolean isNeg = false; int start...

Java

2021-12-31

0 361

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

public class Solution{ int count = 0; public int InversePairs(int[] array){ if(array.length < 2) return 0; mergeSort(array,0,array.length - 1); ret...

Java

2021-12-31

0 417

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

import java.util.*; public class Solution{ PriorityQueue minHeap = new PriorityQueue<>(); PriorityQueue maxHeap = new PriorityQueue<>(new ...

Java

2021-12-31

0 295

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

import java.util.*; public class Solution { PriorityQueue minHeap = new PriorityQueue<>(); PriorityQueue maxHeap = new PriorityQueue<>(new...

Java

2021-12-31

0 309

题解 | #在二叉树中找到两个节点的最近公共祖先# 来自专栏

import java.util.*; public class Solution{ public ArrayList GetLeastNumbers_Solution(int[] input,int k){ ArrayList result = new ArrayList<>(); i...

Java

2021-12-31

0 357