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题解 | #考试分数(五)#
/* select *, rank()over(PARTITION by job order by score) FROM grade SELECT count(*) as c from grade GROUP by job */ SELECT t0.id, t0.job, t0.score, t...
Mysql
2021-09-22
0
214
题解 | #使用子查询的方式找出属于Action分类的所有电影对应的title,description#
select f.title, f.description from film as f where f.film_id in (select fc.film_id from film_category as fc wher...
Mysql
2021-09-21
0
225
题解 | #获取员工其当前的薪水比其manager当前薪水还高的相关信息#
/* #找到员工表 select t.e, t.s, t.d from (select de.emp_no as e, s.salary as s, de.dept_no as d from dept_emp as de join salaries as s on s....
Mysql
2021-09-21
0
275
题解 | #获取所有非manager员工当前的薪水情况#
/* #1.找到非manager的员工 select e.emp_no from employees as e, dept_emp as de where e.emp_no <> de.emp_no */ SELECT de.dept_no, de.emp_no, s.salary FR...
Mysql
2021-09-20
0
276
题解 | #获取当前薪水第二多的员工的emp_no以及其对应的薪水salary#
/* #先找到最大的 select max(s.salary) from salaries */ SELECT e.emp_no, max(s.salary) as salary, e.last_name, e.first_name FROM employees as e join salarie...
Mysql
2021-09-20
0
237
题解 | #统计各个部门的工资记录数#
/* #先查询记录 select count(*) as 'sum' FROM salaries as s left join dept_emp as de on s.emp_no = de.emp_no WHERE dept_no is not NULL GROUP by dept_no */ s...
Mysql
2021-09-20
0
228
题解 | #统计出当前各个title类型对应的员工当前薪水对应的平均工资#
SELECT title, avg(s.salary) FROM titles as t JOIN salaries as s on t.emp_no = s.emp_no GROUP BY title ORDER BY avg(s.salary);
Mysql
2021-09-18
0
200
题解 | #查找employees表emp_no与last_name的员工信息#
SELECT * FROM employees AS e WHERE emp_no % 2 <> 0 AND last_name <> 'Mary' ORDER BY hire_date DESC;
Mysql
2021-09-17
0
237
题解 | #获取所有非manager的员工emp_no#
SELECT e.emp_no FROM employees AS e LEFT JOIN dept_manager AS d ON d.emp_no = e.emp_no WHERE dept_no is NULL;
Mysql
2021-09-17
1
223
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