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题解 | #N个数之和#

fuck = input() nums = map(int,input().split()) sum = 0 for i in nums: sum += i print(sum)

2023-01-14

1 273

题解 | #牛牛逆序输出#

print(input()[::-1])

2023-01-07

1 234

题解 | #牛牛的排列数#

def f(m,n): if n == 1: return m return m * f(m-1,n-1) m,n = map(int,input().split()) print(f(m,n))

2023-01-07

0 224

题解 | #牛牛的Hermite多项式#

def h(n,x): if n == 0: return 1 if n == 1: return 2 return 2 * x * h(n-1,x) - 2*(n-1) * h(n-2,x) n,x = map(int,input().s...

2023-01-07

0 232

题解 | #牛牛的digit#

def digit(x,i): return x[-int(i):] x,i = input().split() print(digit(x,i))

2023-01-06

1 276

题解 | #牛牛的西格玛#

def f(n): if n == 1: return 1 return n + f(n - 1) n = int(input()) print(f(n))

2023-01-06

1 233

题解 | #牛牛的10类人#

def f(n): n = bin(n)[2:] zero = n.count('0') one = n.count('1') if (zero % 2 == 0) and (one % 2 != 0): return '0' elif (o...

2023-01-06

1 237

题解 | #牛牛的四叶玫瑰数#

def func(n,sum = 0): s = str(n) for i in s: sum += int(i) ** 4 if sum == n: return True return False a,b = map(...

2023-01-06

1 280

题解 | #牛牛的替换#

def f(s,a1,a2,a3,a4): if (a1 not in s) and (a3 not in s): return s if a1 in s: s = s.replace(a1,a2) if a3 in s: s ...

2023-01-06

1 227

题解 | #牛牛的素数判断#

def f(n): # 判断 n 是否为素数 if n == 2: return 'true' for i in range(2,n): if n % i == 0: return 'false' return '...

2023-01-06

1 212