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题解 | #今天的刷题量(一)#

select b.name, a.cnt from (select subject_id, count(subject_id) as "cnt" from submission where create_time=current_date() group by subject_id) a join ...

Mysql

2022-03-24

0 148

题解 | #网易云音乐推荐(网易校招笔试真题)#

SELECT DISTINCT c.music_name FROM follow a JOIN music_likes b ON a.follower_id = b.user_id JOIN music c ON b.music_id ...

Mysql

2021-10-30

0 246