牛客101781186号
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题解 | #计算用户的平均次日留存率#
count(distinct device_id) as did_cnt ,COUNT(question_id) FROM question_practice_detail where -- Year(date) ='2021' and month(date)= '8' -- date_forma...
Mysql
2022-01-30
27
488
题解 | #计算用户的平均次日留存率#
正规的连续天计算,应该排序: WITH a AS ( SELECT DISTINCT device_id , date , row_number() OVER (PARTITION BY device_id ORDER BY date) rn FR...
Mysql
2022-01-29
3
337