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全部文章（共29篇）

题解 | 牛牛的空格分隔

while True: try: n = input() print(n,end=' ') except: break

2026-01-21

0 5

题解 | 电商平台需要对商家的销售业绩、退款情况和客户满意度进行综合评估

-- 用 CTE 表达式分步写很清晰 WITH total_sales AS( SELECT merchant_id, SUM(sale_amount) AS total_sales_amount FROM sales_underline GR...

2025-09-20

0 24

题解 | 对商品的销售情况进行深度分析

WITH category_total AS( select category, sum(quantity*price) AS category_total_sum FROM sales JOIN products USING(product_...

2025-09-19

0 35

题解 | 最受欢迎的top3课程

-- top3视频、平均评分不低于3分、pv 倒序、播放时长(一周内) WITH prt AS ( SELECT id, uid, cid, start_time, end_time, TIME...

2025-09-18

0 25

题解 | 查询下订单用户访问次数？

WITH order092 AS( SELECT DISTINCT user_id FROM order_tb WHERE DATE(order_time) = '2022-09-02' ), # 创建临时表来存储仅包含订单日期为2022-09-02数据行的表...

2025-06-09

0 63

题解 | 分析客户逾期情况

SELECT pay_ability, CONCAT(ROUND((count(overdue_days)/count(*))*100,1),'%') AS overdue_ratio # CONCAT 用于输出百分比 FROM loan_tb LEFT JOIN customer_...

2025-06-09

1 51

题解 | 每个月Top3的周杰伦歌曲

# 18-25岁 # 2022年 # 按月和歌曲分组 # 周杰伦歌曲 # 排序和限制，top3 SELECT month, ranking, song_name, play_pv FROM( SELECT song_id, m...

2025-06-05

0 54

题解 | 牛牛的数学作业

T = int(input()) for i in range(T): n = int(input()) a = list(map(int,input().split())) # 接收输入 mean = sum(a) / len(a) variance_value =...

2025-06-05

4 50

题解 | 左侧严格小于计数

# 自己第一遍想出来的答案😂，比较水 n = int(input()) a = list(map(int, input().split())) s = 0 for i in a: sum = 0 for t in a[:s]: if t < i: ...

2025-06-05

0 43

题解 | 神秘石像的镜像序列

a = list(input().split()) for i in a[-2::-1]: print(f'{int(i)} ',end = '')

2025-06-05

0 44