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(共11篇)
题解 | #公共子串计算#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-09-10
0
61
题解 | #公共子串计算#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-09-09
0
62
题解 | #字符串反转#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-09-09
0
66
题解 | #尼科彻斯定理#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-07-24
0
97
题解 | #字符逆序#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-07-24
0
89
题解 | #表达式求值#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-07-24
0
100
题解 | #字符串反转#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-07-24
0
102
题解 | #数字颠倒#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-07-24
0
93
题解 | #进制转换#
const rl = require("readline").createInterface({ input: process.stdin }); var iter = rl[Symbol.asyncIterator](); const readline = async () =...
2024-07-23
0
82
题解 | #【模板】链表#
link = [] for i in range(int(input())): ipt = input().split() if&nb...
Python3
2022-09-01
3
418
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