人间难得此少年a

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题解 | 反向输出一个四位数

#include <stdio.h> int main() { int num = 0; int product_sum = 1; int a = 0; int sum = 0; int count = 0; int sum_count ...

2025-07-01

0 8

题解 | 变种水仙花

#include <stdio.h> int main() { int i = 1; int num = 0; for (i = 10000; i < 100000; i++) { int divide = 10; int number = i; int j ...

2025-07-01

0 8

题解 | 小乐乐算多少人被请家长

#include <stdio.h> int main() { int n, a, b, c = 0; double average = 0; int count = 0; scanf("%d",&n); while ...

2025-06-30

0 13

题解 | 包含数字9的数

#include <stdio.h> int main() { int num = 0; int count = 0; for (int i = 1; i <= 2019; i++) { num = i; while (nu...

2025-06-30

0 13

题解 | 魔法数字变换

#include <stdio.h> int main() { int n = 0; int count = 0; scanf("%d",&n); while (n != 1) { if (n % 2 == 0...

2025-06-30

0 13

题解 | 数位之和

#include <stdio.h> #include <stdlib.h> int main() { int n = 0; int sum = 0; int num = 0; scanf("%d",&n); ...

2025-06-30

0 13

题解 | 牛牛学数列4

#include <stdio.h> int main() { int n = 0; int i = 0; int sum = 0; int Sum_part = 0; scanf("%d",&n); for ...

2025-06-29

0 7

题解 | 牛牛学数列3

#include <stdio.h> int main() { int n = 0; int i, j = 0; int sum = 0; double result = 0; int flag = 1; scanf("%d&q...

2025-06-29

0 7

题解 | 牛牛学数列2

#include <stdio.h> double Sum(int n) { if (n == 1) { return 1; } return 1 * 1.0 / n + Sum(n - 1); } int main() { int n =...

2025-06-29

0 8

题解 | 牛牛学数列

#include <stdio.h> int main() { int num = 0; int sum = 0; int i = 0; scanf("%d",&num); for (i = 1; i <= n...

2025-06-29

0 6