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题解 | 贷款情况

With base as ( select a.*,b.city,c.loan_type_name, d.loan_type_id from loan_applications a left join customers b on a.customer_id = b....

2025-08-25

0 15

题解 | 字符串操作

n,m = map(int,input().split()) s=input() for _ in range(m): l=list(input().split()) s1 = s[0:int(l[0])-1] sm = s[int(l[0])-1:int(l[1])].re...

2025-08-07

0 24