Pedro_json

题解

/ 注册

全部文章 / 题解（共1篇）

题解 | #统计每个用户的平均刷题数#

select university, difficult_level, round((count(qpd.result) / count(distinct qpd.device_id)), 4) avg_answer_cnt from question_practice_detail...

Mysql

2021-12-29

5 824