https://codeforces.com/contest/1157/problem/E
题意:重新排序b数组,使得ci=(ai+bi)%n的字典序最小
题解:用multiset存储b数组,lower_bound查询,不要用vector,容易TLE
/*
*@Author: STZG
*@Language: C++
*/
#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<bitset>
#include<queue>
#include<deque>
#include<stack>
#include<cmath>
#include<list>
#include<map>
#include<set>
//#define DEBUG
#define RI register int
#define endl "\n"
using namespace std;
typedef long long ll;
//typedef __int128 lll;
const int N=200000+10;
const int M=100000+10;
const int MOD=1e9+7;
const double PI = acos(-1.0);
const double EXP = 1E-8;
const int INF = 0x3f3f3f3f;
int t,n,m,k,p,l,r,u,v;
int ans,cnt,flag,temp,sum;
int a[N],b[N],c[N];
multiset<int>d;
char str;
struct node{};
int main()
{
#ifdef DEBUG
freopen("input.in", "r", stdin);
//freopen("output.out", "w", stdout);
#endif
//ios::sync_with_stdio(false);
//cin.tie(0);
//cout.tie(0);
//scanf("%d",&t);
//while(t--){
scanf("%d",&n);
for(int i=1;i<=n;i++){
scanf("%d",&a[i]);
}
for(int i=1;i<=n;i++){
scanf("%d",&b[i]);
d.insert(b[i]);
}
multiset<int>::iterator id;
for(int i=1;i<=n;i++){
m=n-a[i];
id=d.lower_bound(m);
if(id==d.end()){
id=d.lower_bound(0);
}
c[i]=((*id)+a[i])%n;
d.erase(id);
}
for(int i=1;i<=n;i++)
printf("%d%c",c[i]," \n"[i==n]);
//}
#ifdef DEBUG
printf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC);
#endif
//cout << "Hello world!" << endl;
return 0;
}