题解 | 牛牛的线段

#include <math.h>
#include <stdio.h>

int main() {
    int x1, x2, y1, y2 = 0;
    scanf("%d %d",&x1, &y1);
    scanf("%d %d",&x2, &y2);
    printf("%.0lf",pow(x1 - x2, 2) + pow(y1 - y2, 2));
    return 0;
}