B. Catch Overflow!_牛客博客

链接：https://codeforces.com/contest/1175/problem/B

You are given a function ff written in some basic language. The function accepts an integer value, which is immediately written into some variable xx. xx is an integer variable and can be assigned values from 00 to 232−1232−1. The function contains three types of commands:

for nn — for loop;
end — every command between "for nn" and corresponding "end" is executed nn times;
add — adds 1 to xx.

After the execution of the***mands, value of xx is returned.

Every "for nn" is matched with "end", thus the function is guaranteed to be valid. "for nn" can be immediately followed by "end"."add" command can be outside of any for loops.

Notice that "add" commands might overflow the value of xx! It means that the value of xx becomes greater than 232−1232−1 after some "add" command.

Now you run f(0)f(0) and wonder if the resulting value of xx is correct or some overflow made it incorrect.

If overflow happened then output "OVERFLOW!!!", otherwise print the resulting value of xx.

Input

The first line contains a single integer ll (1≤l≤1051≤l≤105) — the number of lines in the function.

Each of the next ll lines contains a single command of one of three types:

for nn (1≤n≤1001≤n≤100) — for loop;
end — every command between "for nn" and corresponding "end" is executed nn times;
add — adds 1 to xx.

Output

If overflow happened during execution of f(0)f(0), then output "OVERFLOW!!!", otherwise print the resulting value of xx.

Examples

input

Copy

9
add
for 43
end
for 10
for 15
add
end
add
end

output

Copy

input

Copy

2
for 62
end

output

Copy

input

Copy

11
for 100
for 100
for 100
for 100
for 100
add
end
end
end
end
end

output

Copy

OVERFLOW!!!

Note

In the first example the first "add" is executed 1 time, the second "add" is executed 150 times and the last "add" is executed 10 times. Note that "for nn" can be immediately followed by "end" and that "add" can be outside of any for loops.

In the second example there are no commands "add", thus the returning value is 0.

In the third example "add" command is executed too many times, which causes xx to go over 232−1232−1.

代码：

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
main()
{
	ll t,n,a=0;
	cin>>t;
	ll m=(1LL<<32);
	string s;
	vector<ll>v;
	v.push_back(1);
	while(t--)
	{
	    cin>>s;
	    if(s=="add")
	        a=a+v.back();
	   if(s=="for")
	   {
	   		cin>>n;
	       v.push_back(min(m,v.back()*n));
	   }
	   if(s=="end")
	       v.pop_back();
	}
	  if(a>=m)cout<<"OVERFLOW!!!";
	    else cout<<a;
	    return 0;
}