链接：https://codeforces.ml/contest/1296/problem/E2

This is a hard version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different.

You are given a string ss consisting of nn lowercase Latin letters.

You have to color all its characters the minimum number of colors (each character to exactly one color, the same letters can be colored the same or different colors, i.e. you can choose exactly one color for each index in ss).

After coloring, you can swap any two neighboring characters of the string that are colored different colors. You can perform such an operation arbitrary (possibly, zero) number of times.

The goal is to make the string sorted, i.e. all characters should be in alphabetical order.

Your task is to find the minimum number of colors which you have to color the given string in so that after coloring it can become sorted by some sequence of swaps. Note that you have to restore only coloring, not the sequence of swaps.

Input

The first line of the input contains one integer nn (1≤n≤2⋅1051≤n≤2⋅105) — the length of ss.

The second line of the input contains the string ss consisting of exactly nn lowercase Latin letters.

Output

In the first line print one integer resres (1≤res≤n1≤res≤n) — the minimum number of colors in which you have to color the given string so that after coloring it can become sorted by some sequence of swaps.

In the second line print any possible coloring that can be used to sort the string using some sequence of swaps described in the problem statement. The coloring is the array cc of length nn, where 1≤ci≤res1≤ci≤res and cici means the color of the ii-th character.

Examples

input

Copy

9
abacbecfd

output

Copy

2
1 1 2 1 2 1 2 1 2

input

Copy

8
aaabbcbb

output

Copy

2
1 2 1 2 1 2 1 1

input

Copy

7
abcdedc

output

Copy

3
1 1 1 1 1 2 3

input

Copy

5
abcde

output

Copy

1
1 1 1 1 1

代码：

#include <bits/stdc++.h>
using namespace std;
long long n,k,t,s=0,s1=0;
char a[200001];
long long dp[200001],ans[30];
map<long long,long long>m;
int main() 
{
	cin>>n;
	cin>>a;
	int flag=1;
	s=0;
	for(int i=0;i<n;i++)
	{
		for(long long j=1;j<=30;j++)
		{
			if(a[i]>=ans[j])
			{
				ans[j]=a[i];
				dp[i]=j;
				s=max(s,j);
				break;
			}
		}
	}
	cout<<s<<endl;
	for(int i=0;i<n;i++)
	cout<<dp[i]<<" ";
	
}