αf′(ξ)+βf(ξ)=0\alpha f^{\prime}(\xi)+\beta f(\xi)=0αf′(ξ)+βf(ξ)=0 => f′(ξ)+βαf(ξ)=0f^{\prime}(\xi)+\frac{\beta}{\alpha} f(\xi)=0f′(ξ)+αβf(ξ)=0
构造：F(x)=eβαxf(x)F(x)=e^{\frac{\beta}{\alpha} x} f(x)F(x)=eαβxf(x)
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