http://120.78.162.102/problem.php?cid=1432&pid=7

http://120.78.162.102/problem.php?id=6244

题解：用计算器按了几下，发现就是求x*v和y*v的和再分别除以v，四舍五入

/*
*@Author:   STZG
*@Language: C++
*/
#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<bitset>
#include<queue>
#include<deque>
#include<stack>
#include<cmath>
#include<list>
#include<map>
#include<set>
//#define DEBUG
#define RI register int
using namespace std;
typedef long long ll;
//typedef __int128 lll;
const int N=10000;
const int MOD=1e9+7;
const double PI = acos(-1.0);
const double EXP = 1E-8;
const int INF = 0x3f3f3f3f;
int t,n,m,k,q;

int main()
{
#ifdef DEBUG
	freopen("input.in", "r", stdin);
	//freopen("output.out", "w", stdout);
#endif
    scanf("%d",&t);
    while(t--){
        scanf("%d",&n);
        ll sum1=0,sum2=0,sum3=0;
        for(int i=1;i<=n;i++){
            scanf("%d%d%d",&m,&k,&q);
            sum1+=m*q;
            sum2+=k*q;
            sum3+=q;
        }
        printf("%.2f %.2f\n",(double)sum1/sum3,(double)sum2/sum3);
    }
    //cout << "Hello world!" << endl;
    return 0;
}