Operations on NFA states
伪代码
put ε-closure({s0}) as an unmarked state into the set of DFA (DStates)
//ε-闭包({s0})是通过ε-跃迁从s0可以访问的所有状态的集合。
while (there is one unmarked S1in DStates) do
begin
mark S1
for each input symbol a do
begin
S2 ← ε-closure(move(S1,a))//set of states to which there is a transition on a from a state s in S1
if (S2 is not in DStates) then
add S2 into DStates as an unmarked state
transfunc[S1,a] ← S2
end
end
push all states in T onto stack;
initialize ε-closure(T) to T;
while stack is not empty do begin
pop t, the top element, off the stack;
for each state u with edge from t to u labeled ε do
if u is not in ε-closure(T) do begin
add u to ε-closure(T) ;
push u onto stack
end
end
使用子集构造法构造DFA。
例题
思路
从状态0开始,我们可以在不消耗任何输入的情况下移动到哪里?
这形成了一个新状态:0,1,2,4,7这个新状态定义了什么转换?
这给出了DFA的转换表Dtran:
Dtran
应用子集构造的结果
DFA
习题
该DFA识别的语言也是a(a | b)*b,求出DFA的转换图
NFA
Dtran
DFA
使用子集构造从NFA构造DFA。
b(a|b)a