题解 | 排序危机

#include <stdio.h>

int main() {
	char data[3][100000] = { "\0" };
	char receive = " ";
	int number = 0;
	int capital = 0;
	int lower_case = 0;
	int n = 0;
	scanf("%d", &n);
	getchar();
	for (int i = 0; i < n; i++) {
		scanf("%c", &receive);
		//数字
		if (receive >= 48 && receive <= 57) {
			data[1][number] = receive;
			number++;
		}
		//大写字母
		else if (receive >= 65 && receive <= 90) {
			data[2][capital] = receive;
			capital++;
		}
		//小写字母
		else {
			data[0][lower_case] = receive;
			lower_case++;
		}
	}
	for (int i = 0; i < 3; i++) {
		for (int j = 0;; j++) {
			if (data[i][j] == '\0') {
				break;
			}
			printf("%c", data[i][j]);
		}
	}
	return 0;
}