无聊的劳伦斯在做测评

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题解 | rin和快速迭代

#include <stdio.h> int divisor(long long x) { double a = 2.0; int i = 1; int count = 0; while (i < a) { // printf("i=%d", i)...

2026-04-02

0 6

题解 | 回文日期

#include <stdio.h> int leap_year(int year) { if (year % 4 == 0 && year % 100 !=0) { return 1; } else if (year % 400 == 0) { retu...

2026-03-27

0 14

题解 | 铺地毯

#include <stdio.h> int main() { int n = 0; scanf("%d", &n); int arr[n][4]; for (int i = 0; i < n; i++) { for (int j = 0;...

2026-03-26

0 11

题解 | 小红的不动点构造

#include <stdio.h> int main() { int n = 0; int k = 0; scanf("%d %d", &n, &k); int remember = k + 1; if (k > n || n - ...

2026-03-25

0 12

题解 | 小红的异或构造

#include <stdio.h> //还原测试数据的输出 int main() { int n = 0; scanf("%d", &n); int a0 = n + 2; int x = 0; for (int i = 1; i <= n...

2026-03-25

1 10

题解 | 构造序列

#include <stdio.h> int main() { int m = 0; int n = 0; scanf("%d %d", &m, &n); if (m > n) { printf("%d", 2 ...

2026-03-25

0 8

题解 | 构造C的歪

#include <stdio.h> int main() { int a = 0; int b = 0; scanf("%d %d", &a, &b); int c = 0; if ((a + b) % 2 == 0) { c = (...

2026-03-25

0 11

题解 | 小红的签到题

#include <stdio.h> int main() { int n = 0; scanf("%d", &n); printf("x_"); for (int i = 2; i < n; i++) { printf...

2026-03-25

0 9

题解 | 小红取数

#include <stdio.h> int main() { int n = 0; scanf("%d", &n); int odd_number = 0; int number = 0; for (int i = 0; i < n; i+...

2026-03-24

0 8

题解 | 小红的不动点分配

#include <stdio.h> int main() { int n = 0; scanf("%d", &n); int arr[2 * 199990] = {0}; int num = 0; int times = 0; for (...

2026-03-23

0 12