调换顺序，注意手动演示一下过程。
关键步骤：
arr[sh[i]] = oldArr[i]
为了避免对arr的覆盖，所以需要另定一个数组，用来保存arr的数据

#include<cstdio>
#include<vector>
#include<cstring>
#include<string>
#include<iostream>
using namespace std;
vector<string> v{"S0","S1","S2","S3","S4","S5","S6","S7","S8","S9","S10","S11","S12","S13",
				 "H1","H2","H3","H4","H5","H6","H7","H8","H9","H10","H11","H12","H13",
				 "C1","C2","C3","C4","C5","C6","C7","C8","C9","C10","C11","C12","C13",
				 "D1","D2","D3","D4","D5","D6","D7","D8","D9","D10","D11","D12","D13",
				 "J1","J2"
				};
int main(){
	int n;
	int arr[60],sh[60],st[60];
	scanf("%d",&n);
	for(int i=1;i<=54;i++){
		scanf("%d",&sh[i]);
	}
	for(int j=1;j<=54;j++){
		st[j]=j;
	}
	for(int i=0;i<n;i++){
		for(int j=1;j<=54;j++){
			arr[sh[j]]=st[j];
		}
		for(int j=1;j<=54;j++){
			st[j]=arr[j];
		}
	}
	for(int i=1;i<=54;i++){
		cout<<v[arr[i]];
		if(i!=54) cout<<" ";
	}
	return 0;
}