https://ac.nowcoder.com/acm/contest/338/K

题解：竟然暴力就行？？？

枚举一条直角边的长度，印证c*c-（枚举的直角边的平方）是不是应该平方数；为了减少时间枚举到c*c/2就行了

/*
*@Author:   STZG
*@Language: C++
*/
#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<bitset>
#include<queue>
#include<deque>
#include<stack>
#include<cmath>
#include<list>
#include<map>
#include<set>
//#define DEBUG
#define RI register int
using namespace std;
typedef long long ll;
//typedef __int128 lll;
const int N=100000+10;
const int MOD=1e9+7;
const double PI = acos(-1.0);
const double EXP = 1E-8;
const int INF = 0x3f3f3f3f;
int t,n,m,k,q,ans;
bool a[N];
char str;
bool sloved(ll c){
    ll c2=c*c;
    for(int i=1;i*i<=c2/2;i++){
        q=sqrt(c2-i*i);
        if(q*q==c2-i*i)
            return 1;
    }
    return 0;
}
int main()
{
#ifdef DEBUG
	freopen("input.in", "r", stdin);
	//freopen("output.out", "w", stdout);
#endif
    while(~scanf("%d",&t))
    while(t--){
        scanf("%d",&n);
        if(sloved(n)){
            cout << "Yes" << endl;
        }else{
            cout << "No" << endl;
        }
    }
    //cout << "Hello world!" << endl;
    return 0;
}