https://ac.nowcoder.com/acm/contest/338/F
C++版本一
题解:DFS
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cfloat>
#include <climits>
#include <iostream>
#include <string>
#include <vector>
#include <list>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <algorithm>
#include <bitset>
using namespace std;
#define LL long long
int T;
LL n;
LL dp[20][4];
int a[20];
int sta[10] = {3, 0, 2, 0, 0, 1, 0, 0, 0, 0};
LL dfs(int pos, int statu, bool limit) {
if(pos == -1) {
return statu == 3? 1: 0;
}
if(!limit && dp[pos][statu] != -1) {
return dp[pos][statu];
}
int up = limit? a[pos]: 9;
LL ans = 0;
for(int i = 0; i <= up; ++i) {
if(statu == 3) {
ans += dfs(pos - 1, 3, limit && i == a[pos]);
continue;
}
if(i == 5) {
ans += dfs(pos - 1, 1, limit && i == a[pos]);
continue;
}
if(sta[i] == statu + 1) {
ans += dfs(pos - 1, sta[i], limit && i == a[pos]);
} else {
ans += dfs(pos - 1, 0, limit && i == a[pos]);
}
}
if(!limit) {
dp[pos][statu] = ans;
}
return ans;
}
LL solve(LL x) {
memset(dp, -1, sizeof(dp));
int pos = 0;
while(x != 0) {
a[pos++] = x % 10;
x /= 10;
}
return dfs(pos - 1, 0, true);
}
int main() {
#ifdef Dmaxiya
freopen("test.txt", "r", stdin);
#endif // Dmaxiya
ios::sync_with_stdio(false);
scanf("%d", &T);
while(T--) {
scanf("%lld", &n);
if(n < 520) {
printf("0\n");
continue;
}
printf("%lld\n", solve(n));
}
return 0;
}
C++版本二
题解:DFS
/*
*@Author: STZG
*@Language: C++
*/
#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<bitset>
#include<queue>
#include<deque>
#include<stack>
#include<cmath>
#include<list>
#include<map>
#include<set>
//#define DEBUG
#define RI register int
using namespace std;
typedef long long ll;
//typedef __int128 lll;
const int N=100000+10;
const int MOD=1e9+7;
const double PI = acos(-1.0);
const double EXP = 1E-8;
const int INF = 0x3f3f3f3f;
ll t,n,m,k,q,ans;
int a[20];
char str;
ll dp[20][100];
ll dfs(int pos,int pre,bool limit){
if(pos==-1)return 1;
if(dp[pos][pre]!=-1&&!limit)return dp[pos][pre];
ll ret=0;
int n=limit?a[pos]:9;
for(int i=0;i<=n;i++){
if(pre==52&&!i)
continue;
ret+=dfs(pos-1,(pre%10)*10+i,limit&&i==a[pos]);
}
if(!limit){
dp[pos][pre]=ret;
}
//cout<<ret<<endl;
return ret;
}
ll solve(ll x) {
memset(dp, -1, sizeof(dp));
int pos = 0;
while(x != 0) {
a[pos++] = x % 10;
x /= 10;
}
return dfs(pos - 1, 0, true);
}
int main()
{
#ifdef DEBUG
freopen("input.in", "r", stdin);
//freopen("output.out", "w", stdout);
#endif
scanf("%lld",&t);
while(t--){
scanf("%lld",&n);
if(n < 520) {
printf("0\n");
continue;
}
printf("%lld\n", n-solve(n)+1);
}
//cout << "Hello world!" << endl;
return 0;
}