题意

  • n*m棋盘，交替染色，不能染的输

思路

  • 奇数先手赢，偶数后手赢
#include<bits/stdc++.h>
using namespace std;
int main(){
    int n,m;
    cin >> n >> m;
    if(n*m%2){
        cout << "akai" << endl;
    }else{
        cout << "yukari" << endl;
    }
    return 0;
}