http://oj.acm.zstu.edu.cn/JudgeOnline/problem.php?id=4230

题解：

模拟除法。

设t为被除数也就是201120112011......

每次输出t/2011，保留t%p；

一直除到他t%p为0为止，记录加了多少次2011。

/*
*@Author:   STZG
*@Language: C++
*/
#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<bitset>
#include<queue>
#include<deque>
#include<stack>
#include<cmath>
#include<list>
#include<map>
#include<set>
//#define DEBUG
#define RI register int
using namespace std;
typedef long long ll;
//typedef __int128 lll;
const int N=100000+10;
const int MOD=1e9+7;
const double PI = acos(-1.0);
const double EXP = 1E-8;
const int INF = 0x3f3f3f3f;
int t,n,m,k,q;
int ans,cnt,flag,temp;
ll a[N];
char str;
int main()
{
#ifdef DEBUG
	freopen("input.in", "r", stdin);
	//freopen("output.out", "w", stdout);
#endif
    //scanf("%d",&n);
    //scanf("%d",&t);
    //while(t--){}
    ll p;
    a[1]=2011;
    for(int i=2;i<=4;i++)
        a[i]=a[i-1]*10000+2011;//cout<<a[i];
    while(~scanf("%lld",&p)){
        ll t=2011;
        cnt=1;
        while(t<p){
            t=t*10000+2011;
            cnt++;
        }
        while(t!=0){
            cout<<t/p;
            t%=p;
            if(t==0)
                break;
            while(t<p){
                t=t*10000+2011;
                cnt++;
            }
        }
        cout<< " " <<cnt<<endl;
    }

    //cout << "Hello world!" << endl;
    return 0;
}