题解 | 牛牛的二三七整除

#include <stdio.h>

int main() {
    int num, i, size = 0;
    int flag = -1;
    scanf("%d", &num);
    int arr[] = { 2, 3, 7 };
    size = sizeof(arr) / sizeof(arr[0]);
    for (i = 0; i < size; i++) {
        if (num % arr[i] == 0 ) {
            printf("%d ",arr[i]);
            flag = 1;
        }
    }
    if (flag == -1) {
        printf("n\n");
    }

}