https://acm.ecnu.edu.cn/contest/125/problem/A/
题解:简单题
实际上就是可以组成数组的和的最大值和最小值之差
/*
*@Author: STZG
*@Language: C++
*/
#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<bitset>
#include<queue>
#include<deque>
#include<stack>
#include<cmath>
#include<list>
#include<map>
#include<set>
//#define DEBUG
using namespace std;
typedef long long ll;
const int N=10000;
const double PI = acos(-1.0);
const double EXP = 1E-8;
const int INF = 0x3f3f3f3f;
ll t,n,m;
ll a,b;
int main()
{
#ifdef DEBUG
freopen("input.in", "r", stdin);
//freopen("output.out", "w", stdout);
#endif
scanf("%d%d%d",&n,&a,&b);
cout << a+b*(n-1)-(a*(n-1)+b)+1<< endl;
//cout << "Hello world!" << endl;
return 0;
}