class Solution {
public:
int Sum_Solution(int n) {
int sum=n;
sum && (sum+=Sum_Solution(n-1));
return sum;
}
public:
int Sum_Solution(int n) {
int sum=n;
sum && (sum+=Sum_Solution(n-1));
return sum;
}
};
//求1+2+3+...+n,要求不能使用乘除法、for、while、if、else、switch、case等关键字及条件判断语句(A?B:C)。/*短路原理